Archie Harrison to see Meghan Markle’s mum Doria as part of ‘low-key’ first US Christmas | Royal | News (Reports)


Meghan Markle and Prince Harry are opting to “keep it chill” for their first Christmas in California, according to Entertainment Tonight. A source has reportedly revealed that the royal couple’s only son, Archie Harrison, will be able to see his grandmother Doria Ragland as part of the celebrations. Although the one-year-old baby Sussex spent his first-ever Christmas in Canada last year, this will be his first in the United States.

The broadcaster said: “The holidays are here and Prince Harry and Meghan Markle are ringing things in with a low-key California Christmas, and the launch of their podcast.

“A source tells ET the couple are planning to keep it chill for their first Christmas in the US.

“They will spend the holiday with their one-year-old son, Archie, and Meghan’s mother, Doria.

“Meghan is expected to lead the cooking with Harry and Doria pitching in.”

READ MORE: Archie Harrison heartbreak: Prince Harry warned of ‘isolating’ son

The Sussexes have already been getting into the Christmas spirit by securing important decorations.

The couple were spotted shopping from a tree at a farm in Santa Barbara.

In a now-deleted post, an employee at the unnamed store talked about the experience.

Meghan and Harry had similarly been seen buying one in the UK a few years ago.

As per tradition, the Royal Family spend their Christmas Day at the Sandringham Estate in Norfolk.

Most senior members turn up for the day as part of a regimented celebration, in which they attended church and exchanged gifts.

However, due to the coronavirus pandemic, none of that will be going ahead this year.

Buckingham Palace announced that the Queen and Prince Philip will spend Christmas quietly in Windsor instead.

The Queen also reportedly will not be going to church on Christmas morning, so as to not encourage people to gather to see her.


This site uses Akismet to reduce spam. Learn how your comment data is processed.